Even as simple as fac 1 = 1 fac n = n * (fac (n - 1)) which is a working Haskell... | Hacker News

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nine_k 65 days ago | parent | context | favorite | on: Why I still reach for Lisp and Scheme instead of H...

Even as simple as

  fac 1 = 1
  fac n = n * (fac (n - 1))

which is a working Haskell implementation?

I mean, in Scheme it is longer to write. I enjoy Lisps and use Emacs for everything, but Haskell can be as terse, or even more terse. (Which is not always a good thing.)

bitwize 64 days ago [–]

I think in terms of token count it comes out to about the same; and Lisp admits fewer kinds of tokens.

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